Sunday, January 15, 2012
Mid-Term Exam
Post your questions here... any question from the first half of the year is welcome... I will list some sample problems from our text that I find particularly interesting... that said any problem from the book is welcome... be sure to post the page and problem number when you ask a question... if possible, write the problem as well as that makes it easier for others (and ME!) to view and respond.
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I get alot of what we have learned this year about graphing but i am having trouble making a graph that goes with a word problem. i am currently doing the additional problems for section 5-5. if some one wants to do these problems and help me it would be greatly appreciated
ReplyDelete#5) A candle begins burning at 7:30pm and decreases in height at a constant rate. Its original height (h) is 12 inches. At 8:00pm, the height of the candle is 8 inches. (Hint: Use 7:30 as time zero on your independent axis)
ReplyDeleteRELATE [The height of a candle over time] is [the initial height] less [the amount in inches it burns down over time]
DEFINE
h is height in inches
m is time in minutes
12 inches is the initial (time zero) height, therefore we should recognize that it is the y-intercept.
The candle burned 4 inches (RISE OF -4) in 15 minutes (RUN of +30), so the rate of change is -4/30 which reduces to -2/15
WRITE
h=f(m)=(-2/15)m + 12
GRAPH
The graph linear graph should be scaled from 0 to 15" on the y-axis (since the candle clearly won't ever be taller than 12") and from 0 to 120 minutes on the x-axis, since at a rate of 4" per 30 minutes, it will burn itself out in 90 minutes).
On your graph, you should have a straight line between the points (0,12) and (90,0).
(0,12) indicates the initial height of the candle
(90,0) indicates that it took 90 minutes for the candle to completely burn down.
Capeesh?
Will Unit 5-8 be on the mid term?
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